:00402B1A 83F87A cmp eax, 0000007A
:00402B1D 7E11 jle 00402B30 <----如果是小写字母,则返回
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:00402B18(C)
:00402B1F 83F831 cmp eax, 00000031
:00402B22 7C05 jl 00402B29
:00402B24 83F839 cmp eax, 00000039
:00402B27 7E07 jle 00402B30 <----如果是数学,则返回
* Referenced by a (U)nconditional or (C)onditional Jump at Address:
:00402B22(C)
:00402B29 83F00E xor eax, 0000000E
:00402B2C 0C31 or al, 31
:00402B2E EBB4 jmp 00402AE4 <----再继续处理.
* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:
:00402B1D(C), :00402B27(C)
:00402B30 C3 ret
---------------------------------------------------------------
---------------------------------------------------------------
---------------------------------------------------------------
注册算法
1.将用户名转化为DWORD值;
2.将DWORD值的4个字节依次转化为字符形式,得到第一组注册码
3.再进行3次变化,依次得到后面3组注册码.
-----------------VC++ 6.0 通过------------------
void CHero3000Dlg::OnOK()
{
char name[512];
unsigned char code1[5];
unsigned char code2[5];
unsigned char code3[5];
unsigned char code4[5];
int namelen;
long reg1,reg2,reg3,reg4,temp;
int i,n;
this->UpdateData();
memset(name,0,512);
namelen = this->m_name.GetLength();
strcpy(name,this->m_name);
for(i=0;i<namelen;i++)
{
name[i] = change(i,name[i]);
}
i = (namelen / 4);
if((namelen % 4)>0) i++;
reg1 = 0;
for(n=0;n<i;n++)
{
memcpy(&temp,&name[n*4],4);
reg1 += temp;
_asm mov eax,reg1;
_asm mov ecx,n;
_asm ror eax,cl;
_asm mov reg1,eax;
}
memcpy(code1,®1,4);
for(i=0;i<4;i++)
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